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In Δ ABC, the median AD is 6 cm and CB is 12 cm, measure of angle CAB is
AD = 6 cm and BC = 12 cm
Since, AD is the median, => BD = DC = 6 cm
In $$\triangle$$ ADC, => AD = CD = 6 cm
=> $$\angle$$ DCA = $$\angle$$ DAC = 45°
Similarly, in $$\triangle$$ ADB => $$\angle$$ DAB = 45°
$$\therefore$$ $$\angle$$ CAB = $$\angle$$ DAC + $$\angle$$ DAB = 45° + 45° = 90°
=> Ans - (A)
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