Question 77
Two students appeared for an examination. One of them secured 21 marks more than the other and his marks were 80% of the sum of their marks. The marks obtained by them are
Solution
Let marks scored by 1st student = $$x$$
=> Marks scored by another student = $$(x + 21)$$
According to question, => $$(x + 21) = \frac{80}{100} \times (x + x + 21)$$
=> $$x + 21 = \frac{4}{5} \times (2x + 21)$$
=> $$5x + 105 = 8x + 84$$
=> $$8x - 5x = 105 - 84 = 21$$
=> $$x = \frac{21}{3} = 7$$
$$\therefore$$ Marks scored by other student = 7 + 21 = 28
=> Ans - (C)
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