Question 76

Mansukh can do a piece of work in 10 hours. If he is joined by Jayanti who is 50% more efficient, in what time will they together finish the work?

Solution

Let total work to be done = 20 units

Mansukh's efficiency = $$\frac{20}{10} = 2$$ units/hr

Jayanti is 50% more efficient than Mansukh, => Jayanti's efficiency = $$\frac{150}{100} \times 2 = 3$$ units/hr

=> Mansukh and Jayanti 1 day's work = 2 + 3 = 5 units/hr

$$\therefore$$ Time taken by them to finish the work together = $$\frac{20}{5} = 4$$ hours

=> Ans - (C)

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