If $$3e^x \tan ydx + (1 - e^x) \sec^2 ydy = 0$$, then $$y$$ is

A

$$\tan y = c(1 + e^{x})^3$$

B

$$y = c(1 - e^{x})^3$$

C

$$\log y = c(1 + e^{x})^3$$

D

$$\tan y = c(1 - e^{x})^3$$