For $$[\text{FeF}_6]^{3-}$$ and $$[\text{CoF}_6]^{3-}$$, the statement that is correct is

A

both are colored

B

both are colorless

C

$$[\text{FeF}_6]^{3-}$$ is colored and $$[\text{CoF}_6]^{3-}$$ is colorless

D

$$[\text{FeF}_6]^{3-}$$ is colorless and $$[\text{CoF}_6]^{3-}$$ is colored