Question 75

What is the value of $$\frac{1}{7} \times \frac{1}{8} \div \frac{1}{4} + \frac{1}{3} \times \frac{1}{9} + \frac{1}{6} \div \frac{1}{12}$$ of $$\frac{3}{7}$$?

Solution

= $$\frac{1}{7} \times \frac{1}{8} \div \frac{1}{4} + \frac{1}{3} \times \frac{1}{9} + \frac{1}{6} \div \frac{1}{12}$$ of $$\frac{3}{7}$$

= $$\frac{1}{7}\times\frac{1}{8}\times4+\frac{1}{27}+\frac{1}{6}\div\frac{1}{28}$$

= $$\frac{1}{7}\times\frac{1}{2}+\frac{1}{27}+\frac{1}{6}\times\ \frac{28}{1}$$

= $$\frac{1}{14}+\frac{1}{27}+\frac{14}{3}$$

= $$\frac{27+14+1764}{378}$$

= $$\frac{1805}{378}$$

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