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In triangle ABC, D and E are two points on the sides AB and AC respectively so that DE $$\parallel$$ BC and $$\frac{AD}{BD} = \frac{5}{6}$$. The ratio of the area of $$\triangle$$ABC to the area of trapezium DECB is:
96 : 121
121 : 96
36 : 121
121 : 36
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