In triangle ABC, D and E are two points on the sides AB and AC respectively so that DE $$\parallel$$ BC and $$\frac{AD}{BD} = \frac{5}{6}$$. The ratio of the area of $$\triangle$$ABC to the area of trapezium DECB is:

A

96 : 121

B

121 : 96

C

36 : 121

D

121 : 36