Question 75
If O is the circumcenter of ABC and $$OBC = 35^\circ$$ , then the BAC is equal to
Solution
OB = OC = radius of the circle
$$ < OBC = < OCB = 35^\circ $$
$$ < BOC = 180 - 70 = 110^\circ $$
$$ < BAC = \frac{110}{2} = 55^\circ $$ [ the angle subtended at the centre by an arc is twice to the angle subtended at the circumference]
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