Question 75

If O is the circumcenter of ABC and $$OBC = 35^\circ$$ , then the BAC is equal to

Solution

OB = OC = radius of the circle

$$ < OBC = < OCB = 35^\circ $$

$$ < BOC = 180 - 70 = 110^\circ $$

$$ < BAC = \frac{110}{2} = 55^\circ $$ [ the angle subtended at the centre by an arc is twice to the angle subtended at the circumference]

Share on Whatsapp Share on Whatsapp

Create a FREE account and get: