If $$A = 2 \div 3 \times 4, B = 3 of 4 + (7 - 2)$$ and $$C = 4 + 5 - 6$$, then what is the value of $$A + B + C$$?
$$A = 2 \div 3 \times 4, B = 3 of 4 + (7 - 2)$$ and $$C = 4 + 5 - 6$$
First solve bracket then apply bodmas rule
$$A =\frac {8}{3} $$
B = $$3 of 4 + (7 - 2)$$Â
  = $$12 + 5$$
  = 17
C =Â $$4 + 5 - 6$$
  =3
Then
A+B +C=Â $$\frac {8}{3} $$ +17 +3
          =$$\frac {68}{3}$$
Â
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