If $$6\sec \theta = 10$$, then find the value of $$\frac{(5\cosec \theta - 3 \cot \theta)}{(4 \cos \theta + 3 \sin \theta)}$$.

A

$$\frac{2}{3}$$

B

$$\frac{3}{2}$$

C

$$\frac{5}{6}$$

D

$$\frac{6}{5}$$