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For real numbers $$x$$, y, define two binary operations $$\odot$$ and $$\ominus$$ by
$$x \odot y = x^{2} + y^{2} + 3xy - 5$$$$x \ominus y = 3x + 4y + 5xy + 6$$ then$$(1 \odot 2) \ominus (2 \odot 3) = $$
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