Question 74
Two numbers are, respectively, 25% and 30% less than a third number. What is the ratio of the first two numbers, in the order mentioned in the previous statement?
Solution
Let's assume the third number is 100y.
Two numbers are, respectively, 25% and 30% less than a third number.
First number = 100y of (100-25)%
= 100y of 75%
= $$100y\times\frac{75}{100}$$
= 75y
Second number = 100y of (100-30)%
= 100y of 70%
= $$100y\times\frac{70}{100}$$
= 70y
Ratio of the first two numbers, in the order mentioned in the previous statement = 75y : 70y
= 15 : 14
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