Question 74

The value of $$27 + [3 (50 - 20) + 168 \div 4 + 2 - 11 \times 2]$$ is:

Solution

$$27+[3(50-20)+168\div4+2-11\times2]$$ = $$27+[3(30)+168\div4+2-11\times2]$$

= $$27+[90+42+2-11\times2]$$

= $$27+[90+42+2-22]$$

= $$27+[132-20]$$

= $$27+112$$

= $$139$$

Hence, the correct answer is Option D

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