Solution
$$27+[3(50-20)+168\div4+2-11\times2]$$ = $$27+[3(30)+168\div4+2-11\times2]$$
= $$27+[90+42+2-11\times2]$$
= $$27+[90+42+2-22]$$
= $$27+[132-20]$$
= $$27+112$$
= $$139$$
Hence, the correct answer is Option D
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