Question 74

The ratio of the ages of two persons is 3 : 4. If the age of one of them is greater than the other by 8 years, then what is the sum of their ages?

Solution

Let the ages of both the persons to be x and y. Then,

$$\frac{x}{y}$$=$$\frac{3}{4}$$

x =3$$\times\frac{y}{4}$$,

x = y-8

putting x value in the given equation. so y-8 = 3$$\times\frac{y}{4}$$

$$\frac{y}{4}$$ = 8

y = 32

x = y-8 = 32-8 = 24

Hence total ages of x and y = 24 +32= 56.

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