In $$\triangle ABC, D$$ and E are the points on the sides Ab and AC, respectively such that $$\angle AED = \angle ABC$$. If AE = 6 cm, BD = 2 cm, DE = 3 cm and BC = 5 cm, then (AB + AC) is equal to:

A

$$\frac{86}{3}$$ cm

B

$$\frac{49}{3}$$ cm

C

$$\frac{50}{3}$$ cm

D

$$\frac{70}{3}$$ cm