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Solution
Given, 2A = 3B = 7C
2A = 3B
$$\dfrac{A}{B} = \dfrac{3}{2}$$ -- (1)
3B = 7C
$$\dfrac{B}{C} = \dfrac{7}{3}$$ -- (2)
Multiplying (1) by 7 and (2) by 2
$$\dfrac{A}{B} = \dfrac{21}{14}$$
$$\dfrac{B}{C} = \dfrac{14}{6}$$
Therefore, $$A : B : C = 21 : 14 :Â 6$$
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