Question 74

Eighteen years ago, the ratio of A’s age to B’s age was 8:13 Their present ratios are 5 :7 What is the present age of A ?

Solution

let the ages of A and B 18 years ago be 8x and 13x

So there present ages will be

A= 8x +18

B = 13x + 18

It is given that ,

$$\frac{8x+18}{13x + 18}$$ = $$\frac{5}{7}$$

x = 4

So present age of A = 8x + 18 = 32 +18 = 50 years

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