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Question 74
A can do a certain job in 12 days. B is 60% more efficient than A. To do the same job B alone would take?
Solution
Let the total work be 60 days.
Efficiency of A = 60/12 = 5 units per day
Efficiency of B = 160% of Efficiency of A = 160% of 5 = 8 units per day
Therefore, B can do the work in $$\dfrac{60}{8} = 7\dfrac{1}{2}$$ days
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