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Question 73
Which is the least four-digit number which when divided by 5, 6 and 8 leaves remainder 2 in each case?
Solution
LCM of 5,6 and 8 is 120
Required number will be in the form of 120x+2 as all leave same remainder 2
We require least 4 digit number and so for x=9 we have 120*9+2=1080+2
=1082Â
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