Question 73

Walking $$\frac{5}{7}$$ of his usual speed, a person reaches his office 10 minutes later than the usual time. His usual time in minutes is:

Solution

If the person is walking at 5/7th of his speed , he is taking 7/5th of his usual time.

Let the usual time be x. Extra time is 2/5th of x.

$$\frac{2}{5}x$$ =10

x= 25

So , the answer would be option c)25 minutes.

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