The population of a town is increasing at the rate of 10% per year. If the present population of the town is 1,00,000, what will its population be 2 years from now?
If the present population of the town is 1,00,000.
present population of the town =Â 1,00,000
The population of a town is increasing at the rate of 10% per year.
population of the town after 2 years from now = 1,00,000 of (100+10)% of (100+10)%
= 1,00,000 of 110% of 110%
=Â $$1,00,000\times\frac{110}{100}\times\frac{110}{100}$$
=Â $$1000\times11\times11$$
= 121000
Create a FREE account and get:
Detailed syllabus & Topic-wise Weightage
By proceeding you agree to create your account
Free CAT Syllabus PDF will be sent to your email address soon !!!
