The given table represents the number of computers sold by four dealers A, B, C and D during the first six months of 2016. Study the table carefully and answer the question that follows.
The number of months, in which the number of computers sold by dealer B was less than the average number of computers sold by dealer C over six months, was:
Solution
Average number of computers sold by dealer C over six months = total number of computer/6 = $$\frac{95 + 104 + 100 + 99 + 100 + 102}{6}$$ = 600/6 =100
The number of months, in which the number of computers sold by dealer B wasless than the average number of computers sold by dealer C over six months, was 4(January, feb, march, April)
