The following Pie chart represents the percentage-wise distribution of 800 students of class XII in a school in six different sections A, B, C, D, E and F.

The table given below shows the number of girls of class XII in six different sections A, B, C, D, E and F.

The total number of girls in sections B, C and D together is what percent more than the total number of boys in sections A, B and D together?

Number of students in section A = $$\frac{20}{100}\times$$800 = 160

Number of boys in section A = 160 - 102 = 58

Number of students in section B = $$\frac{18}{100}\times$$800 = 144

Number of boys in section B = 144 - 80 = 64

Number of students in section D = $$\frac{17}{100}\times$$800 = 136

Number of boys in section D = 136 - 98 = 38

Total number of boys in sections A, B and D together = 58 + 64 + 38 = 160

Total number of girls in sections B, C and D together = 80 + 104 + 98 = 282

Required percentage = $$\frac{282-160}{160}\times$$100

= $$\frac{122}{160}\times$$100

= 76.25%

Hence, the correct answer is Option B