Question 73

The diagonal of a square is 24 cm. What is its perimeter?

Solution

Given,

Diagonal of a square = 24.

we know that, Diagonal of a square = $$\sqrt{2}a$$

therefore, $$\sqrt{2}a$$ = 24

a = $$\frac{24}{\sqrt{2}}$$

Perimeter of a square = 4a

4a = $${4}\times{\frac{24}{\sqrt{2}}}$$

= $${2{\sqrt{2}}}\times{24}$$

= $${48}{\sqrt{2}}$$

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