Solution
Given,
Diagonal of a square = 24.
we know that, Diagonal of a square = $$\sqrt{2}a$$
therefore, $$\sqrt{2}a$$ = 24
a = $$\frac{24}{\sqrt{2}}$$
Perimeter of a square = 4a
4a = $${4}\times{\frac{24}{\sqrt{2}}}$$
= $${2{\sqrt{2}}}\times{24}$$
= $${48}{\sqrt{2}}$$
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