Question 73

If the side of a square increases by 20%, then what will be percent increase in its perimeter?

Solution

Let side of the square be 10 cm
Perimeter of the square = 4*10 = 40 cm
Side increased by 20%
New side of the square = 120% of 10 = 12 cm
Perimeter of the square = 4*12 = 48 cm
Percentage increase in the perimeter = $$\dfrac{48-40}{40}\times100 = \dfrac{8}{40}\times100 = 20$$%

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If the side of a square increases by 20%, then what will be percent increase in its perimeter?

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