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General solution of the differential equation $$(D^2 - 2D + 1)y = e^x$$ is
$$Ae^x + Be^{-x} + \frac {x^2}{2}e^x$$
$$e^x (A + Bx) - \frac {x^2}{2}e^x$$
$$Ae^x + Be^{-x} - \frac {x^2}{2}e^x$$
$$e^x (A + Bx) + \frac {x^2}{2}e^x$$
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