If the imaginary part of $$\frac {2z + 1}{iz + 1}$$ is —2, then the locus of the point z in the complex plane is

A

x + 2y - 2 = 0

B

2x + y - 2 = 0

C

x - 2y - 2 = 0

D

x + 2y + 2 = 0