A sum of ₹800 invested on simple interest becomes ₹1200 in 8 years. What will be simple interest for 6 years on the sum at the same rate of interest?
SI= $$\frac{(P\times R\times T)}{100}$$
Given , P= 800 RS
T= 8 years
SI= Amount - P= 1200-800 = 400 Rs
SI = $$\frac{(400\times R\times8)\ \ }{100}$$
R = (25/4) or 6.25
Now, given , T= 6 Years, P = 800 Rs, R= 6.25%
SI = $$\frac{(800\times6\times6.25)}{100}$$ = ₹300
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