Question 72

What is the value of $$\left(1 + \frac{3}{4}\right) \times \frac{3}{21}  of  5\frac{1}{3} \div \frac{128}{49} + \frac{2}{3} \times \frac{7}{11} \times \frac{121}{49} \div \left(\frac{15}{14} - \frac{2}{7}\right)$$?

Solution

 $$\left(1 + \frac{3}{4}\right) \times \frac{3}{21}  of  5\frac{1}{3} \div \frac{128}{49} + \frac{2}{3} \times \frac{7}{11} \times \frac{121}{49} \div \left(\frac{15}{14} - \frac{2}{7}\right)$$

 $$\frac{7}{4}\times \frac{3}{21}  of  5\frac{1}{3} \div \frac{128}{49} + \frac{2}{3} \times \frac{7}{11} \times \frac{121}{49} \div \frac{11}{14}$$

$$\frac{7}{4}\times \frac{16}{21}\div \frac{128}{49}+\frac{2}{3} \times \frac{7}{11} \times \frac{121}{49} \div \frac{11}{14}$$


$$\frac{7}{4}\times \frac{7}{24}+\frac{2}{3} \times \frac{7}{11} \times \frac{22}{7}$$

$$\frac{49}{96}+\frac{4}{3}$$

$$\frac{177}{96}$$

$$\frac{59}{32}$$


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