The ratio of the present age of Mahesh and Ajay is 3 : 2 respectively. After 8 years. Ratio of their age will be 11: 8. What will be the present age of Mahesh’s son if his age is half of the present age of Ajay?
Let the present ages of Mahesh and Ajay be 3x years and 2x years respectively.
Then, Their ages after 8 years will be 3x+8 years and 2x+8 years.
Given, $$\dfrac{3x+8}{2x+8} = \dfrac{11}{8}$$
$$24x+64 = 22x+88$$
=> $$2x = 24$$
=> $$x = 12$$
Then, Present ages of Mahesh and Ajay are 36 years and 24 years respectively.
Present age of Mahesh's son = Half of Present age of Ajay = 12 years.
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