Select the number that will come in place of the question mark (?) in the following mathematical statement.
$$(9^{2} \times 27 + 3^{3} \times 7 + ?)^{\frac{1}{2}} = 59$$
Let's assume 'y' in place of the question mark.
$$(9^{2} \times 27 + 3^{3} \times 7 + y)^{\frac{1}{2}} = 59$$
Square on both sides.
$$(9^2\times27+3^3\times7+y)^{\frac{1}{2}\times\ 2}=59^2$$
$$(81\times27+27\times7+y)=3481$$
(2187+189+y) = 3481
2376+y = 3481
y = 3481-2376
= 1105
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