Find the total surface area of a cube whose volume is $$64 cm^3$$ ?.
Given, Volume of the cube $$= 64 cm^3$$
Then, Side of the cube $$= 4 cm$$
Total Surface area of the cube $$= 6 \times \text{side}^2 = 6\times4^2 = 6\times16 = 96 cm^2$$
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