Question 71

The population of a town increases at the rate of 15% per annum. If the present population is 108445 of town, then what was the population 2 years ago?

Solution

Let population 2 years ago = $$100x$$

Population after 1st year increasing by 15% = $$100x\times(\frac{115}{100})=115x$$

Population after 2nd year = $$115x\times(\frac{115}{100})=132.25x$$

According to ques,

=> $$132.25x=108445$$

=> $$x=\frac{108445}{132.25}=820$$

$$\therefore$$ Population 2 years ago = $$100\times820=82000$$

=> Ans - (C)

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