The given graph shows the performance of the students of schools A, B, C, D, E and F in a Board Examination. Study the graph and answer the questions that follow.
The average number of students (per school) who failed in schools A, B C and E is approximately what percentage less than the number of students who passed without distinction in school D?
Solution
School Total Passed Distinction Without distinction Failed
A 800 640 300 340 160
B 1050 840 350 490 210
C 1200 920 450 470 280
D 750 600 260 340 150
E 900 750 330 420 150
F 1500 1000 450 550 500
Using our collected data, we can easily calculate the average number of students who failed in A, B, C and E to be $$(160+210+280+150)/4=800/4=200$$
The number of students who passed without distinction is 340.
Ratio of these two values is $$\frac{200}{340}=0.588$$
Which means that the average number of students who failed in A, B, C and E is 41.176% smaller than the number of students who passed without distinction in D.
This is approximately 41%.
Therefore, Option A is the correct answer.
