Question 71

The area of the four walls of a room having length 6 m, breadth 4 m and height 4 m, is:

Solution

Length = 6 m, breadth = 4m, height = 4 m

The area of the four walls of a room = $$2(length \times height) + 2(breadth \times height)$$

= $$2(6 \times 4) + 2(4 \times 4)$$ = 48 + 32 = 80 $$m^2$$

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