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Question 71
Let x be the greatest number such that when 12085, 16914 and 13841 are divided by it, the remainder in each case is same. The sum of digits of x is:
Solution
As in this case each number leaves the same remainder we have to find the HCF of differences of the three numbers i.e
13841-12085=1756
16914-13841=3073
16914-12085=4829
HCF of these three numbers is 439
sum=4+3+9=16
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