In $$\triangle ABC, \angle B = 90$$. AD and CE are the medians drawn from A and C, respectively. If AC = 10 cm and $$AD = \sqrt{55}$$ cm, then the length of CE is:

A

$$2\sqrt{15}$$ cm

B

$$\sqrt{70}$$ cm

C

$$\sqrt{66}$$ cm

D

$$5\sqrt{3}$$ cm