In a mixture of 60 liters, milk and water are in the ratio 2:1. find the quantity of water to be added to make the ratio 4:3
Milk in the mixture $$=\frac{2}{3}\times60 =40$$
Water in the mixture$$=\frac{1}{3}\times60=20$$
Let x be the water added to the mixture
According to question,
$$\frac{40}{x+20}=\frac{4}{3}$$
$$\Rightarrow x = 10$$
Option B is correct.
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