Question 71
Find the greatest number that will divide 47, 95 and 187 so as to leave the same remainder in each case.
Solution
In each case they leave the same remainder and so the HCF of differences between the numbers has to be taken
Difference 1=95-47=48
Difference 2=187-47=140
Difference 1=187-95=92
HCF of 48,140 and 92
48=2*2*2*2*3
140=2*2*5*7
92=2*2*23
HCF=4
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