Question 71

A’s salary is 20% less than B’s salary. Then B’s salary is more than A’s salary by

Solution

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Let B's salary be Rs.100x.
Then, A's salary = (100-20)% of 100x = Rs.80x
Hence, Required percentage = $$\dfrac{100x-80x}{80x} = \dfrac{20x}{80x}\times100 = 25\%$$

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