Question 71

2 sec$$^{2}$$A is equal to

Solution

Expression : 2 sec$$^{2}$$A

= $$sec^2 A + sec^2 A$$

Using, $$sec^2 A = 1 + tan^2 A$$

= $$(1 + tan^2 A) + (1 + tan^2 A)$$

Adding and subtracting $$2 tan A$$

= $$(1 + tan^2 A - 2tan A) + (1 + tan^2 A + 2tan A)$$

= $$(1 - tan A)^2 + (1 + tan A)^2$$

=> Ans - (D)

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