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Question 70
What is the value of $$\frac{7}{11} \div \frac{21}{33} \times \frac{5}{12} + \frac{10}{36} \times \frac{6}{11} \div \frac{18}{33}?$$
Solution
=Â $$\frac{7}{11} \div \frac{21}{33} \times \frac{5}{12} + \frac{10}{36} \times \frac{6}{11} \div \frac{18}{33}$$
=Â $$\frac{7}{11}\times\frac{33}{21}\times\frac{5}{12}+\frac{10}{36}\times\frac{6}{11}\times\frac{33}{18}$$
= $$1\times\frac{5}{12}+\frac{10}{36}\times1$$
=Â $$\frac{5}{12}+\frac{10}{36}$$
= $$\frac{15}{36}+\frac{10}{36}$$
= $$\frac{25}{36}$$
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