Question 70

What is the value of $$\frac{7}{11} \div \frac{21}{33} \times \frac{5}{12} + \frac{10}{36} \times \frac{6}{11} \div \frac{18}{33}?$$

Solution

= $$\frac{7}{11} \div \frac{21}{33} \times \frac{5}{12} + \frac{10}{36} \times \frac{6}{11} \div \frac{18}{33}$$

= $$\frac{7}{11}\times\frac{33}{21}\times\frac{5}{12}+\frac{10}{36}\times\frac{6}{11}\times\frac{33}{18}$$

= $$1\times\frac{5}{12}+\frac{10}{36}\times1$$

= $$\frac{5}{12}+\frac{10}{36}$$

= $$\frac{15}{36}+\frac{10}{36}$$

= $$\frac{25}{36}$$


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