Question 70
The average of 4 consecutive numbers is 64.5. What is the largest number among these numbers?
Solution
In the 4 consecutive numbers, let's assume the smallest number is 'y'.
So the 4 consecutive numbers will be y, (y+1), (y+2), (y+3)
The average of 4 consecutive numbers is 64.5.
$$y+(y+1)+(y+2)+(y+3) = 64.5\times4$$
4y+6 = 258
4y = 258-6
4y = 252
y = 63
The largest number among these numbers = (y+3)
= (63+3)
= 66
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