In $$\triangle ABC, D$$ and $$E$$ are points on sides $$AB$$ and $$AC$$, such that $$DE \parallel BC$$. If $$AD = x + 3, DB = 2x − 3, AE = x + 1$$ and $$EC = 2x − 2$$, then the value of x is:

A

$$\frac{1}{5}$$

B

$$\frac{4}{5}$$

C

$$\frac{3}{5}$$

D

$$\frac{1}{2}$$