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A solution contains acid and water in the ratio of 4 : 5. If 20% of the solution is replaced by water, then what will be the ratio of acid and water in the new solution?
Let the volume of Milk be 400 ml and the volume of water be 500 ml.
20% of the solution is replaced by water.
Remaining milk after replacement = $$400\times\left(1-\dfrac{1}{5}\right)=320$$ ml
Water in the new solution = $$500\times\left(1-\frac{1}{5}\right)+180=580$$ ml
Ratio = 320 : 580 = 16:29
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