Question 7
The smallest positive integer $$n$$ for which $$18900 \times n$$ is a perfect cube is
Solution
TO BE FILLED - printed options need checking. Since $$18900 = 2^2 \times 3^3 \times 5^2 \times 7$$, the exponents of 2, 5 and 7 must be raised to multiples of 3, which needs $$n = 2 \times 5 \times 7^2 = 490$$, a value that does not appear among the options printed for this problem.
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