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The number of real numbers $$x$$ which satisfy $$\frac{8^x+27^x}{12^x+18^x}=\frac{7}{6}$$ is
Put $$a=2^x$$ and $$b=3^x$$. The equation becomes $$\frac{a^3+b^3}{a^2b+ab^2}=\frac{7}{6}$$, which simplifies to $$6a^2-13ab+6b^2=0$$. Hence $$(3a-2b)(2a-3b)=0$$, giving $$\left(\frac{2}{3}\right)^x=\frac{2}{3}$$ or $$\left(\frac{2}{3}\right)^x=\frac{3}{2}$$. Therefore $$x=1$$ or $$x=-1$$, so there are $$2$$ real solutions.
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