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An aeroplane flies with an average speed of 756 km/h. A helicopter takes 48 h to cover twice the distance covered by aeroplane in 9 h. How much distance will the helicopter cover in 18 h? (Assuming that flights are non-stop and moving with uniform speed.)
Speed of the aeroplane = 756 km/h.
It is given that twice the distance covered by the aeroplane in 9 hrs is equal to the distance covered by the helicopter in 48 hrs.
Distance covered by the aeroplane in 9 hrs = 756*9 = 6804 km.
Speed of the helicopter = $$\ \frac{2\times\ 6804\ }{48}$$ = 283.5
Distance covered by the helicopter in 18 hrs = 283.5*18 = 5103 km.
D is the correct answer.
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