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Question 69
If $$x + y + z = 3 and xy + yz + zx = -18$$,then what is the value of $$x^3 + y^3 + z^3 - 3xyz = ?$$
Solution
Formula,
$$x^3 + y^3 + z^3 - 3xyz$$ = $$(x +y + z)*((x + y + z)^2 - 3(xy +yz +zx))$$
Put the required values , we get = 189
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