SSC CGL 24th August 2021 Shift-1

Question 69

If $$x + \frac{1}{x} = 7$$, then $$x^2 + \frac{1}{x^2}$$ is equal to:

Solution

$$x+\frac{1}{x}=7$$

Squaring on both sides,

$$x^2+\frac{1}{x^2}+2.x.\frac{1}{x}=49$$

$$x^2+\frac{1}{x^2}+2=49$$

$$x^2+\frac{1}{x^2}=47$$

Hence, the correct answer is Option A

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